Question : Find the area of triangle ABC where
angle ABC = 35 degrees
angle BCA = 110 degrees
angle CAB = 35 degrees
AND, length BC = 4 cm
ANSWER:
Description Step1 : b = AC = BC because triangle ABC is isosceles
Triangle ABC are isosceles because angle ABC=angle BAC=35 degree
Description Step2 : sin 70 degrees = h/4
0.9369=h/4
h = 0.9369*4 = 3.759
Step3: Area = 0.5*b*h = 0.5*(4)(3.759) = 7.518 cm2
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