Here is a simple example for you:
Question:
Assume that your friend, Omar, had two job interviews, and now estimates he has
a 40% chance of getting the first job, and also a 40% chance of getting each job.
What are his chances of getting at least one job offer?
What are his chances of getting neither job?
What are his chances of getting offered both jobs?
Answer:
Chances of getting each job = 40% = .4
So chances of not getting the jobs = 1- .4 = 6
Now chances of getting at least one job includes the
chances of getting any one job and chances of getting both.
Chances of getting any one job = 2x(.4x .6) = .48
Chances of getting both = .4x .4x = .16
So required probability = .48 + .16 = .64 or 64%
Now chances of getting neither job = 1 -chances of getting at least one job
= 1 - .64 = .36 or 36%
Chances of getting both jobs offered = .4 * .4 = .16 or 16%
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