Simple Form in Math

Introduction to simple form in math:

In mathematics simple form means simplest form or simplifying. Fractions are simplifying means dividing by the value of GCF for both numerator and denominator. Here GCF stands for greatest common divisor. Simple form in decimal means converting whole number or rounding the value. Therefore, simple form is a reducing of values for the given.


Example problems of simple form in math:


Simple form in math problem 1:

Writing the simple form: `18/12`

Solution:

Given `18/12`

Method 1:

First we are factoring the values of numerator and then factoring a denominator values.

Finally reduce the fraction by cancelling the common value.

Method 2:

Find the Greatest common divisor for the given fraction values and then simplifying them.

Therefore we can simply the given problem using the second method.

Greatest common divisor of 18, 12= 6

So, `(18-:6)/(12-:6)=3/2`

Answer: `3/2`

Simple form in math problem 2:

Writing the simple form: `28/16`

Solution:

Given `28/16`

Method 1:

First we are factoring the values of numerator and then factoring a denominator values.

Finally reduce the fraction by cancelling the common value.

Method 2:

Find the Greatest common divisor for the given fraction values and then simplifying them.

Therefore we can simply the given problem using the second method.

Greatest common divisor of 28, 16= 4

So, `(28-:4)/(16-:4)= 7/4`

Answer: `7/4`

Simple form in math problem 3:

Simplify  `(x(x+7)-4(x+7))/( x+7)`

Solution:

We can simplify the given fraction values by using the following steps:

First we are factoring the values of numerator and then factoring a denominator values.

Finally reduce the fraction by cancelling the common value.

Given `(x(x+7)-4(x+7))/( x+7)`

Here we can doing only reducing fraction. Because of already have factors for both numerator and denominator.

So reduce the fraction individually and then simplifying that,

`(x(x+7)-4(x+7))/( x+7)=(x(x+7))/(x+7)-(4(x+7))/(x+7)`

Here cancel the factor `x+7 ` on both numerator and denominator.

After simplifying, we get the final answer.

`(x(x+7)-4(x+7))/( x+7)= x-4`

Answer: ` x-4`


Practice problems of simple form in math:


Write the simple form: `55/22`
Simplify `(x(x+4)+3(x+4))/( x+4)`
Answer:

1)      `5/2`

2)    ` (x+3)`

Math Practice 6th Grade

Introduction to Math Practice 6th grade:

The topics involved in Math Practice 6th grade are  place values, addition, subtraction, rounding& estimation, multiplication, measurement, division, fractions, area, comparing and ordering numbers, surface area, volume, Geometric properties and expressions. In this article we shall discuss about the math practice 6th grade. The following are the examples involved in  math practice 6th grade.

Understanding Formula for Area of Triangle is always challenging for me but thanks to all math help websites to help me out.

Math Practice 6th Grade Problems:


Example 1: Solve 2x + 5 = 15

Solution:Given: 2x + 5 = 15

Subtracting 5 on both sides,we get

2x + 5 – 5 = 15 – 5

2x = 10

Dividing 4 on both sides, we get

2x = 10
2      2

x = 5

Example 2: Find the area of a parallelogram of length 9 inches and height of 9 inches.

Solution: Formula : Area of parallelogram = length * height

Given: length = 9 inches, height = 9 inches.

So, area of parallelogram = 9 * 9 = 81 square inches.

Example 3: Find the volume of a cube with length of side equal to 13.

Solution: Formula to find the volume of a  cube = (length of the given side)3

Given: Length of the side = 13

So, Volume of a cube  = (13)3

= 13 * 13 * 13

=2197.

Example 4:  Find the area of a rectangle with base of length is 3 inches and height of 2 inches.

Solution:Area of a rectangle = length * height

So, Area of a rectangle =3 * 2

= 6 square inches.

Example 5: 95 is what percent of 100?

Solution: Perform the division operation from first number by the second number.

`95 divided by100`=>(`95/100` ) = 0.95

Multiply the answer(0.95) by 100

0.95 * 100 = 95

So 30 is 95% of 100.

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Math Practice Problems 6th Grade:


Example 1: Solve x + 5 = 10

Answer: x = 5

Example 2: Find the area of a parallelogram of length 6 inches and height of 2 inches.

Answer:  12 square inches.

Example 3: Find the volume of a cube with length of side equal to 6.

Answer: 216

Example 4: Find the area of a rectangle with base of length is 8 inches and height of 3 inches.

Answer: 24 square inches.

Example 5: 73 is what percent of 100?

Answer:  73%

Word Problems Math Work Done

Introduction:
The numbers and variables in a problem which are given in the form of words are known as word problems. It is hard to translate the words into mathematical expression or equations. When it is done, then it is easy to solve those problems. But translation of those words to mathematical symbols or equation is hard. Understanding the word problem is more important than solving it. Without understanding the math word problems the solving work can’t be done. Understanding What is Arithmetic Mean? is always challenging for me but thanks to all math help websites to help me out.


Steps in solving Word problems:


The following are the steps to be considered when solving math word problems,

Step 1:  The first step in solving the word problems is, translating the given word data’s into numbers.

Step 2: After translation to numbers, read the problem completely and understand what is asked to find?

Step 3: Next step is to name the unknown values using variables like x, y z etc. This will help to solve the problem easily.

Step 4: After naming the unknown variables, work out the problem in an organized manner using basic arithmetic operations like addition, subtraction, multiplication and division.

For example, if a word problem consists of two equations, first find the value of one unknown variable and then substitute that value in any one of the equation to find the another  value.


Math word problem work done examples:


Example 1: At present, the ratio between the ages of Anand and Ram is 3: 4. After 5 years, Anand's age will be 29 years. What is the age of Ram at present?

Solution:

Let the age of Anand = 3x

Let the age of Ram = 4x

3x + 5 = 29

Subtract 5 on both sides,

3x + 5 – 5 = 29 – 5

3x = 24

Divide 3 on both sides,

3x/3 = 24/3

x = 8

Ram age = 4(8)

= 32 yrs

Ram age is 32 years.

Example 2: Raj has some hens and sheep’s. If the number of heads is 50 and the number of feet equals 144, what will be the number of hens?
Solution:

Let the number of hens = x

Let the number of sheep’ = y

x + y = 50        equation 1

2x + 4y = 144    equation 2

Multiply equation 1 with 2,

2x + 2y = 100

2x + 4y = 144   (subtracting)

-2y = -44

-2y = -44

Divide 2 on both sides,

-2y/2 = -44/2

y = 22

Plug in y value in equation 1

x + y = 50

x + 22 = 50

Subtract 22 on both sides,

x + 22 – 22 = 50 – 22

x = 28

The number of hens is 28.

World Math Day

Introduction to world math day:

World math day is not a day to celebrate for mathematics. It is an international competition in math. World math day was started in 2007 on March 14. The date can be written as 3.14.2007. The first four numbers is same as the value of pi. So this world math day can also be say as pi day.


Playing method:


The trademark names are world maths day and world math day. Usually the questions are based on the basic math multiplication, division, addition, subtraction and equations. The students are required to answer each game in one minute. When one student is playing a game the website will find the same level player and make that player to play against the player. If there is no such competitor was found then the player will start to play against the computer. After completing the game the result of both the competitors will be individually send.

The organizer of this event is an Australian. From 235 countries over 1.13 million students participated in 2010 math world day which was conducted on March 3rd. The entire student totally solved 479,732,613 math questions correctly.


Age category and levels:


There are three categories to play a game. The category is based on ages. The three categories are 5-8 ages, 9-13 ages and 14-18 ages. The student who answered correctly for large number questions is a world champion. The champion will awarded by minted gold medal. There is a separate medal for each age group topper.

The top 10 students in each group who answered more questions correctly will receive a gold medal. All the students who answered more than 4000 questions with correct solutions will receive a world maths day gold award. The top 50 students in each group who answered more questions correctly will receive a printed certificate gold award. If the whole class was participated then the top 10 classes will receive a world math day trophy in each group. The top 50 classes in each group who answered more questions correctly will receive a printed certificate gold award.

Fast Ways To Do Math

Introduction to fast ways to do math:

Mathematics provides the solutions to solve the problem by defining mathematical definitions. However during solving the complex problems it consumes more time and the process becomes tedious. Many mathematical experts provide the fast, easy ways to do math problems. Here we deal with the fast way to do the math problems in the following sessions. Please express your views of this topic Introduction to Mathematical Logic by commenting on blog.


Fast ways to do math:


Many mathematical experts provides us the easy fast ways to learn maths, in the following parts we will see some of the fast ways to do math problems,

Fast ways to do math multiplication of the two digit numbers using 11:

For a two digit number that multiplies with 11, follow the steps for fast multiplication,

For example: Take the number 45

45 * 11

Consider the number 45.
Add 4 +5 = 9
Now insert the 9 inbetween the 4 and 5, gives 495.
We got the final answer 495 fastly using this ways.

Another example:

Take the number 25

25 * 11

Consider the number 25.
Add 2 +5 = 7
Now insert the 7 inbetween the 2 and 5, gives 275.
We got the final answer 275 fastly using this ways.


Fast ways to do math multiplication of the two digit numbers using 16:


For a two digit number that multiplies with 16, follow the steps for fast multiplication,

For example: Take the number 44

44 * 16

Consider the number 44.
Multiply the given number with 10 gives 44*10 = 440.
Then take the half value of the given number, and multiply with 10.
Gives (44 * 1 /2  ) * 10

= 22 * 10

= 220

Now add all the computed terms in above steps with the given number,
= 440 + 220 + 44

= 704

Thus we got the answer as fast as possible using this ways.

We got the final answer 495 fastly.

Another example:

Take the number 64

64 * 16

Consider the number 64.
Multiply the given number with 10 gives 64*10 = 640.
Then take the half value of the given number, and multiply with 10.
Gives (64 * 1 /2  ) * 10

= 32 * 10

= 320

Now add all the computed terms in above steps with the given number,
= 640 + 320 + 64

= 1024

Thus we got the answer 1024 as fast as possible using this ways.

Story Problems in Math

Introduction about story problems in math:

Story problems are also known as word problems which are mainly used for kids to apply their knowledge of mathematics to the real world problem.  Story problems in math develop thinking power, problem-solving skills, and reasoning ability among students. Story problems in math are a sequence of expressions that fits into an equation. We will see some math story problems in this article.

Example Story problems in math:


Example 1: There are 25 pencils in the box. 13 pencils were used by the kids. How many pencils are there remaining?

Solution:

Total Number of Pencils in box = 25

Number of pencils used = 13

Remaining pencils = 25 -13

= 12

Example 2: Rahul, Joey, Nizam were playing Carom. Rahul scored 55 points, Joey scored 42 points and Nizam scored 30 points. How many points did they score together?

Solution:

Points scored by Ravi = 55

Points scored by John = 42

Points scored by Nizad = 30

Total points scored = 55+42+30

= 127 points.

Example 3: Joseph is 3 ½   cm Shorter than Sara.  Sara is 162 `3/10` cm tall.  How tall is Joseph?

Solution:

Given Sara height = 162 `3/10`

Joseph height = Sara height - 3½

= 162 `3/10 ` – 3 ½

= 162`3/10` – 7/2

= (1623 – 35)/ 10

= `1588/10`

= 158 `8/10`

Joseph height is 158 `8/10` cms.

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More Example Story problems in math:

Example 4:

There are 5 tigers and 6 lions. The tigers each weigh 15 pounds. The lions each weigh 20 pounds. How much do they weigh altogether?

Solution:

Number of Tiger= 5

Number of Lion= 6

Weight of 1 Tiger = 15 pounds

Weight of 5 Tigers = 5 * 15

= 75 pounds

Weight of 1 Lion = 20 pounds

Weight of 6 Lions = 20*6

= 120 pounds

Total weight = 120+75

= 195 pounds

Example 5: Sanjana bought 25 Balloons for `$` 5. What is the cost of 1 balloon?

Solution:

Number of balloons= 25

Cost of 30 balloons = `$` 5

Cost of 1 balloon    = `5/25`

= `$` 0.2

Example 6: In a Conference, among the total number of people 12 people came to the meeting late which is the 24% of the total count. How many people are there in that Conference hall totally?

Solution:

Total number of people = x

Number of people arrived late =12 (4% of x)

Hence,

`(24/100) ` * x = 12

24x= 12 *100

24x = 1200

X= `1200/24`

= 50

Hence Total numbers of people are 50.